URI-1074

URI Online Judge | 1074

Even or Odd

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Problem link Click here

Read an integer value N. After, read these N values and print a message for each value saying if this value is odd, even, positive or negative. In case of zero (0), although the correct description would be "EVEN NULL", because by definition zero is even, your program must print only "NULL", without quotes.

Input

The first line of input is an integer N (N < 10000), that indicates the total number of test cases. Each case is a integer number X (-107 < X <107)..

Output

For each test case, print a corresponding message, according to the below example. All messages must be printed in uppercase letters and always will have one space between two words in the same line.

Input Sample	Output Sample
4 -5 0 3 -4	ODD NEGATIVE NULL ODD POSITIVE EVEN NEGATIVE

Solution...

#include<stdio.h>
int main()
{
    int t,n,i;
    scanf("%d",&t);
    for(i=1;i<=t;i++){
        scanf("%d",&n);
        if(n%2!=0){
            if(n>0){
                printf("ODD POSITIVE\n");
            }
            else if(n<0){
                printf("ODD NEGATIVE\n");
            }
        }
        if(n%2==0){
            if(n>0){
                printf("EVEN POSITIVE\n");
            }
            else if(n<0){
                printf("EVEN NEGATIVE\n");
            }
        }
        if(n==0){
            printf("NULL\n");
        }
    }
    return 0;
}