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Read the start time and end time of a game, in hours and minutes (initial hour, initial minute, final hour, final minute). Then print the duration of the game, knowing that the game can begin in a day and finish in another day,
Obs.: With a maximum game time of 24 hours and the minimum game time of 1 minute.
Input
Four integer numbers representing the start and end time of the game.
Output
Print the duration of the game in hours and minutes, in this format: “O JOGO DUROU XXX HORA(S) E YYY MINUTO(S)” . Which means: the game lasted XXX hour(s) and YYY minutes.
Input Sample | Output Sample |
7 8 9 10 | O JOGO DUROU 2 HORA(S) E 2 MINUTO(S) |
7 7 7 7 | O JOGO DUROU 24 HORA(S) E 0 MINUTO(S) |
7 10 8 9 | O JOGO DUROU 0 HORA(S) E 59 MINUTO(S) |
Solution...
#include <stdio.h>
int main()
{
int st, sm, et, em, rm, rt;
scanf("%d %d %d %d", &st, &sm, &et, &em);
rt = et - st;
if (rt < 0){
rt = 24 + (et - st);
}
rm = em - sm;
if (rm < 0){
rm = 60 + (em - sm);
rt--;
}
if (et == st && em == sm){
printf("O JOGO DUROU 24 HORA(S) E 0 MINUTO(S)\n");
}
else
printf("O JOGO DUROU %d HORA(S) E %d MINUTO(S)\n", rt, rm);
return 0;
}
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