URI-1035

URI Online Judge | 1035

Selection Test 1

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Problem link Click here

Read 4 integer values A, B, C and D. Then if B is greater than C and D is greater than A and if the sum of C and D is greater than the sum of A and B and if C and D were positives values and if A is even, write the message “Valores aceitos” (Accepted values). Otherwise, write the message “Valores nao aceitos” (Values not accepted).

Input

Four integer numbers A, B, C and D.

Output

Show the corresponding message after the validation of the values​​.

Input Sample	Output Sample
5 6 7 8	Valores nao aceitos

2 3 2 6

Valores aceitos

Solution....

#include<stdio.h>
int main()
{
    int a,b,c,d;
    scanf("%d%d%d%d",&a,&b,&c,&d);
    if(b>c && d>a && (c+d)>(a+b) && c>0 && d>0 && a%2==0){
        printf("Valores aceitos\n");
    }
    else
    {
        printf("Valores nao aceitos\n");
    }
    return 0;
}

URI-1037

URI Online Judge | 1037

Interval

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Problem link Click here

You must make a program that read a float-point number and print a message saying in which of following intervals the number belongs: [0,25] (25,50], (50,75], (75,100]. If the read number is less than zero or greather than 100, the program must print the message “Fora de intervalo” that means "Out of Interval".

The symbol '(' represents greather than. For example:
[0,25] indicates numbers between 0 and 25.0000, including both.
(25,50] indicates numbers greather than 25 (25.00001) up to 50.0000000.

Input

The input file contains a floating-point number.

Output

The output must be a message like following example.

Input Sample	Output Sample
25.01	Intervalo (25,50]

25.00

Intervalo [0,25]

100.00

Intervalo (75,100]

-25.02

Fora de intervalo

Solutin......

#include<stdio.h>

int main()
{
    double n;
    scanf("%lf",&n);
    if(n<0 || n>100){
        printf("Fora de intervalo\n");
    }
    else if(n<=25.00){
        printf("Intervalo [0,25]\n");
    }
    else if(n<=50.0){
        printf("Intervalo (25,50]\n");
    }
    else if(n<=75.0){
        printf("Intervalo (50,75]\n");
    }
    else if(n<=100.0){
        printf("Intervalo (75,100]\n");
    }
    return 0;
}